In many real-life situations, two or more people or machines work together to complete a task faster. This idea is called combined work. For example, imagine painting a wall: if one painter can finish the job in 4 hours, and another in 6 hours, how long will it take if both work together? This kind of question involves understanding how individual work rates combine to complete the total work.
Understanding combined work is vital for competitive exams like engineering or medical entrances, as it tests logical reasoning and mathematical skills. It also appears in everyday scenarios such as calculating how long a group of people will take to complete a project, or how machines sharing a load affect overall efficiency.
To solve these problems, we must first learn the relationship between work, time, and work rate, and how multiple workers' rates add up.
Let's define the three key terms:
These are connected by simple formulas:
| Formula | Interpretation | Example |
|---|---|---|
Work = Rate x Time | The total work is the product of rate and time. | If a worker paints 2 m² per hour and works for 3 hours, work done = 2 x 3 = 6 m². |
Rate = Work / Time | Rate is how much work is done per unit time. | If a job requires 1 unit of work and is done in 4 hours, rate = 1 / 4 = 0.25 units/hour. |
Time = Work / Rate | Time taken to complete work at a given rate. | To complete 1 unit of work at rate 0.5 units/hour takes 1 / 0.5 = 2 hours. |
When two or more workers work together, their individual rates add up to form the combined work rate.
Why does this happen? Because the amount of work done in one hour by both working simultaneously is the sum of work done by each individually in that hour.
For example, if Worker A can finish a job in 5 hours, their rate is \( \frac{1}{5} \) work units per hour. If Worker B can finish the same job in 10 hours, their rate is \( \frac{1}{10} \). Working together, their combined rate is:
\[ \frac{1}{5} + \frac{1}{10} = \frac{2}{10} + \frac{1}{10} = \frac{3}{10} \text{ work units per hour} \]So together, they can complete \( \frac{3}{10} \) of the job in 1 hour, taking:
\[ \frac{1}{\frac{3}{10}} = \frac{10}{3} = 3\frac{1}{3} \text{ hours} \]This is faster than either working alone.
graph TD A[Find individual times or work rates] B[Convert times to rates: R = 1 / T] C[Add individual rates to get combined rate] D[Calculate total time: T = 1 / (combined rate)] A --> B --> C --> D
Special cases:
Step 1: Calculate individual work rates.
Rate of A = \( \frac{1}{6} \) job/hour
Rate of B = \( \frac{1}{8} \) job/hour
Step 2: Find combined work rate.
Combined rate = \( \frac{1}{6} + \frac{1}{8} = \frac{4}{24} + \frac{3}{24} = \frac{7}{24} \) job/hour
Step 3: Calculate time taken by both together.
Time = \( \frac{1}{\frac{7}{24}} = \frac{24}{7} = 3.43 \) hours, or 3 hours 26 minutes approximately.
Answer: Working together, A and B will complete the job in approximately 3 hours 26 minutes.
Step 1: Find individual rates.
X's rate = \( \frac{1}{12} \) job/hour
Y's rate = \( \frac{1}{15} \) job/hour
Z's rate = \( \frac{1}{20} \) job/hour
Step 2: Calculate combined work rate.
Combined rate = \( \frac{1}{12} + \frac{1}{15} + \frac{1}{20} \) = \( \frac{5}{60} + \frac{4}{60} + \frac{3}{60} = \frac{12}{60} = \frac{1}{5} \) job/hour.
Step 3: Calculate total time required.
Time = \( \frac{1}{\frac{1}{5}} = 5 \) hours.
Answer: All three working together complete the task in 5 hours.
Step 1: Calculate individual rates (consider filling as positive, emptying as negative).
Rate of A = \( \frac{1}{4} \) tank/hour (filling)
Rate of B = \( \frac{1}{6} \) tank/hour (filling)
Rate of C = \( -\frac{1}{12} \) tank/hour (emptying)
Step 2: Find combined rate.
Combined rate = \( \frac{1}{4} + \frac{1}{6} - \frac{1}{12} \)
Convert to common denominator 12:
\( \frac{3}{12} + \frac{2}{12} - \frac{1}{12} = \frac{4}{12} = \frac{1}{3} \) tank/hour
Step 3: Calculate total time to fill the tank.
Time = \( \frac{1}{\frac{1}{3}} = 3 \) hours.
Answer: It will take 3 hours to fill the tank when all pipes are open together.
Step 1: Calculate work done by A in 3 hours.
A's rate = \( \frac{1}{10} \) job/hour
Work done by A in 3 hours = \( 3 \times \frac{1}{10} = \frac{3}{10} \) of the job
Step 2: Find remaining work.
Remaining work = \( 1 - \frac{3}{10} = \frac{7}{10} \) of the job
Step 3: Find combined rate of A and B.
B's rate = \( \frac{1}{15} \) job/hour
Combined rate = \( \frac{1}{10} + \frac{1}{15} = \frac{3}{30} + \frac{2}{30} = \frac{5}{30} = \frac{1}{6} \) job/hour
Step 4: Calculate time for A and B together to finish remaining work.
Time = Work / Rate = \( \frac{7}{10} \div \frac{1}{6} = \frac{7}{10} \times 6 = \frac{42}{10} = 4.2 \) hours
Step 5: Calculate total time to complete the job.
Total time = 3 hours (A alone) + 4.2 hours (A and B together) = 7.2 hours
Answer: They will finish the job in 7.2 hours, i.e., 7 hours 12 minutes.
Step 1: Find individual rates.
P's rate = \( \frac{1}{8} \) job/hour
Q's rate = \( \frac{1}{12} \) job/hour
R's rate = \( \frac{1}{6} \) job/hour
Step 2: Find amount of work done by each in 4 hours.
Work by P = \( 4 \times \frac{1}{8} = \frac{1}{2} \)
Work by Q = \( 4 \times \frac{1}{12} = \frac{1}{3} \)
Work by R = \( 4 \times \frac{1}{6} = \frac{2}{3} \)
Step 3: Total work done = \( \frac{1}{2} + \frac{1}{3} + \frac{2}{3} = \frac{1}{2} + 1 = \frac{3}{2} \)
Note: total work done is more than 1 full job because work done is considered cumulatively.
Step 4: Calculate share of each worker in the total work.
P's share = \( \frac{1/2}{3/2} = \frac{1/2}{3/2} = \frac{1}{3} \)
Q's share = \( \frac{1/3}{3/2} = \frac{1/3}{3/2} = \frac{2}{9} \)
R's share = \( \frac{2/3}{3/2} = \frac{2/3}{3/2} = \frac{4}{9} \)
Step 5: Find payment amount for each.
Total payment = Rs.6000
P's payment = \( \frac{1}{3} \times 6000 = Rs.2000 \)
Q's payment = \( \frac{2}{9} \times 6000 = Rs.1333.33 \)
R's payment = \( \frac{4}{9} \times 6000 = Rs.2666.67 \)
Answer: The payments are Rs.2000 to P, Rs.1333.33 to Q, and Rs.2666.67 to R.
When to use: Whenever dealing with total work, assume it equals 1 unit regardless of complexity.
When to use: When multiple workers or machines are working simultaneously.
When to use: Problems involving pipes filling and draining tanks.
When to use: Workers start or stop at different times within the task.
When to use: Payment or cost sharing problems in partnerships or teamwork.
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